[ot][spam][crazy][spam][confused code] asdf!
Undescribed Horrific Abuse, One Victim & Survivor of Many
gmkarl at gmail.com
Mon Jul 17 13:39:27 PDT 2023
> # remainings[0] = 0
> # remainings[1] = min_period
> # remainings[remaining_count] = remaining
> # >>> def remainings(idx, remaining_count, remaining, min_delay):
> # ... a = (remaining / remaining_count - min_delay) / (remaining_count -
> 1)
> # ... b = min_delay - a
> # ... return a * idx * idx + b * idx
ok hash out context issue.
remaining here i'm not sure what it means.
it's defined as the time left at remainings[remaining_count]
i guess that would be mark_time. the time of last execution. now we
want to know the delay for the next time.
so then
remainings[remaininng_count] = eta - mark_time
# remainings[0] = 0
# remainings[1] = min_period
# remainings[remaining_count] = eta - mark_time
# >>> def remainings(idx, remaining_count, eta, mark_time, min_delay):
# ... a = ((eta - mark_time) / remaining_count - min_delay) /
(remaining_count - 1)
# ... b = min_delay - a
# ... return (a * idx + b) * idx
we could then recast everything based on absolute times which might be
clearer for me
after some thought and noting i guess that means just subtracting from
eta at first
# reversetimepoint[0] = eta
# reversetimepoint[1] = eta - min_delay
# reversetimepoint[remaining_count] = mark_time
# >>> def reversetimepoints(idx, remaining_count, eta, mark_time, min_delay):
# ... a = (mark_time / remaining_count - min_delay) / (remaining_count - 1)
# ... b = eta - min_delay - a
# ... return eta - (a * idx + b) * idx
want to solve for a,b,c again
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