imaginary halting problem was Re: [spam][crazy][spam] imaginary code resembling trained dissociation

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in one possible extreme f() outputs a warning that g() will not halt
for trillions of years because it has to brute force f(), but there’s
a small chance that it will halt if it does this by chance, and it
continues compute to figure this out.

it’s interesting there that maybe f() can’t gamble that g() won’t halt
maybe because g() could identify this and halt: and the need to not
make that gamble is in a quite similar space to cryptographic
guarantees being probabilistic in general.