"lossless" optical waveguide - loss floor in glass media
coderman
coderman at protonmail.com
Sun Sep 8 15:05:52 PDT 2019
‐‐‐‐‐‐‐ Original Message ‐‐‐‐‐‐‐
On Sunday, September 8, 2019 9:27 PM, jim bell <jdb10987 at yahoo.com> wrote:
...
> In order to evaluate this as a proposed idea, a physicist would consider:
>
> 1. The loss of manufactured optical waveguides did indeed hit an unexplained 'floor' in the early 1980s, about 0.16 db/kilometers of loss.
> 2. The manufacturers and users of such fibers have had a very powerful motivation to figure out how to lower their loss to well below 0.16 db/kilometers, for nearly 40 years.
> 3. Nothing has yet been found, or it would have been employed.
> 4. Photons do indeed possess an oscillating magnetic field.
> 5. A nucleus of an isotope with 'spin' does indeed behave as magnetic dipole.
> 6. Such a nucleus should be mechanically affected by the passage of light.
> 7. Energy should be transferred from that light to the nucleus, and thus the atom, as the light passes.
> 8. Removing most or all atoms with an electromagnetic 'spin' should remove this loss mechanism, in proportion to the amount of such isotopes remaining.
>
> Do you have any other ideas as to how that loss is manifested?
i wonder if Rayleigh scattering is sufficient to account for the floor? unfortunately this is quite complicated in glass media; i don't know how to answer the question :/
(e.g. the static shear modulus of glass multiplies the factors involved in determining a scattering coefficient...)
best regards,
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